(p^3-3p)+(2p^2+4p-1)+(4p^3-3)=

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Solution for (p^3-3p)+(2p^2+4p-1)+(4p^3-3)= equation: 


Simplifying
(p3 + -3p) + (2p2 + 4p + -1) + (4p3 + -3) = 0

Reorder the terms:
(-3p + p3) + (2p2 + 4p + -1) + (4p3 + -3) = 0

Remove parenthesis around (-3p + p3)
-3p + p3 + (2p2 + 4p + -1) + (4p3 + -3) = 0

Reorder the terms:
-3p + p3 + (-1 + 4p + 2p2) + (4p3 + -3) = 0

Remove parenthesis around (-1 + 4p + 2p2)
-3p + p3 + -1 + 4p + 2p2 + (4p3 + -3) = 0

Reorder the terms:
-3p + p3 + -1 + 4p + 2p2 + (-3 + 4p3) = 0

Remove parenthesis around (-3 + 4p3)
-3p + p3 + -1 + 4p + 2p2 + -3 + 4p3 = 0

Reorder the terms:
-1 + -3 + -3p + 4p + 2p2 + p3 + 4p3 = 0

Combine like terms: -1 + -3 = -4
-4 + -3p + 4p + 2p2 + p3 + 4p3 = 0

Combine like terms: -3p + 4p = 1p
-4 + 1p + 2p2 + p3 + 4p3 = 0

Combine like terms: p3 + 4p3 = 5p3
-4 + 1p + 2p2 + 5p3 = 0

Solving
-4 + 1p + 2p2 + 5p3 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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